I have a shell script with a syntax compatible to both bash and zsh, except for a section that has zsh specific syntax that throws syntax errors if sourced from bash. Is there an easy way to escape such section when using bash?

The script is a bash function that sources all the files in a directory. It works fine from zsh (and it is irrelevant to the question).

#!/usr/bin/env bash

shell=$(ps -p $$ -oargs=)

if [ $shell = "bash" ]; then
	for f in ~/.functions.d/*.sh; do source $f; done
elif [ $shell = "zsh" ]; then
	for f (~/.functions.d/**/*.sh) source $f
fi

The error raised when sourcing it in bash is:

scr: line 8: syntax error near unexpected token `('
scr: line 8: `  for f (~/.functions.d/**/*.sh) source $f'

Relevant links:

• This same question in Stack Overflow.
• Unix & Linux: Source only part of a script from another script?
• Stack Overflow: Using source to include part of a file in a bash script.

posted over 2 years ago

CC BY-SA 4.0

2y ago by dsr‭

4015.alt‭

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