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Q&A A shell script that can run under different shells

I have a shell script with a syntax compatible to both bash and zsh, except for a section that has zsh specific syntax that throws syntax errors if sourced from bash. Is there an easy way to escap...

2 answers · posted 2y ago by 4015.alt‭ · last activity 2y ago by mjy‭

Question shell bash shell-scripting zsh

#4: Post edited by

dsr‭ · 2021-12-25T20:39:44Z (over 2 years ago)
I recommend a title change for clarity in searching.

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~~How to not source a part of a bash script?~~

A shell script that can run under different shells

I have a shell script with a syntax compatible to both `bash` and `zsh`, except for a section that has zsh specific syntax that throws syntax errors if sourced from bash.
Is there **an easy way** to escape such section when using bash?

---

The script is a bash function that sources all the files in a directory. It works fine from zsh (and it is irrelevant to the question).

```shell
#!/usr/bin/env bash

shell=$(ps -p $$ -oargs=)

if [ $shell = "bash" ]; then
	for f in ~/.functions.d/*.sh; do source $f; done
elif [ $shell = "zsh" ]; then
	for f (~/.functions.d/**/*.sh) source $f
fi
```

The error raised when sourcing it in `bash` is:

    scr: line 8: syntax error near unexpected token `('
    scr: line 8: `  for f (~/.functions.d/**/*.sh) source $f'

---

Relevant links:

- [This same question in Stack Overflow.](https://stackoverflow.com/questions/70382141/how-to-prevent-sourcing-a-part-of-a-bash-script)
- [Unix & Linux: Source only part of a script from another script?](https://unix.stackexchange.com/questions/242854/source-only-part-of-a-script-from-another-script)
- [Stack Overflow: Using source to include part of a file in a bash script.](https://stackoverflow.com/questions/22183903/using-source-to-include-part-of-a-file-in-a-bash-script)

shell bash shell-scripting zsh

#3: Post edited by

Quasímodo‭ · 2021-12-17T22:37:25Z (over 2 years ago)
Add the proper error message; Add link to crosspost; Spelling/Punctuation.

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~~I have a shell script with a syntax compatible to both `bash` and `zsh`, except for a section that has zsh specific syntax. that throws syntax errors if sourced from a bash~~
~~is there **an easy way** to escape such section when using bash.~~
---
~~The script is a bash function that sources all the files in a directory. it works fine form zsh (and it is irrelevant to the question)~~
```shell
#!/usr/bin/env bash
shell=$(ps -p $$ -oargs=)
if [ $shell = "bash" ]; then
for f in ~/.functions.d/*.sh; do source $f; done
elif [ $shell = "zsh" ]; then
for f (~/.functions.d/**/*.sh) source $f
fi
```
~~the error is produced by the 7th line, when sourcing it in `bash`~~
---
~~relevant links~~
~~- https://unix.stackexchange.com/questions/242854/source-only-part-of-a-script-from-another-script~~
~~- https://stackoverflow.com/questions/22183903/using-source-to-include-part-of-a-file-in-a-bash-script~~

I have a shell script with a syntax compatible to both `bash` and `zsh`, except for a section that has zsh specific syntax that throws syntax errors if sourced from bash.
Is there **an easy way** to escape such section when using bash?
---
The script is a bash function that sources all the files in a directory. It works fine from zsh (and it is irrelevant to the question).
```shell
#!/usr/bin/env bash
shell=$(ps -p $$ -oargs=)
if [ $shell = "bash" ]; then
for f in ~/.functions.d/*.sh; do source $f; done
elif [ $shell = "zsh" ]; then
for f (~/.functions.d/**/*.sh) source $f
fi
```
The error raised when sourcing it in `bash` is:
scr: line 8: syntax error near unexpected token `('
scr: line 8: ` for f (~/.functions.d/**/*.sh) source $f'
---
Relevant links:
- [This same question in Stack Overflow.](https://stackoverflow.com/questions/70382141/how-to-prevent-sourcing-a-part-of-a-bash-script)
- [Unix & Linux: Source only part of a script from another script?](https://unix.stackexchange.com/questions/242854/source-only-part-of-a-script-from-another-script)
- [Stack Overflow: Using source to include part of a file in a bash script.](https://stackoverflow.com/questions/22183903/using-source-to-include-part-of-a-file-in-a-bash-script)

#2: Post edited by

4015.alt‭ · 2021-12-16T17:31:13Z (over 2 years ago)
typos

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I have a shell script with a syntax compatible to both `bash` and `zsh`, except for a section that has zsh specific syntax. that throws syntax errors if sourced from a bash
is there **an easy way** to escape such section when using bash.
---
~~The script is a bash function that sources all the files in a directory. it works fine form zsh (and it is irreverent to the question)~~
```shell
#!/usr/bin/env bash
shell=$(ps -p $$ -oargs=)
if [ $shell = "bash" ]; then
for f in ~/.functions.d/*.sh; do source $f; done
elif [ $shell = "zsh" ]; then
for f (~/.functions.d/**/*.sh) source $f
fi
```
the error is produced by the 7th line, when sourcing it in `bash`
---
~~revilement links~~
- https://unix.stackexchange.com/questions/242854/source-only-part-of-a-script-from-another-script
- https://stackoverflow.com/questions/22183903/using-source-to-include-part-of-a-file-in-a-bash-script

I have a shell script with a syntax compatible to both `bash` and `zsh`, except for a section that has zsh specific syntax. that throws syntax errors if sourced from a bash
is there **an easy way** to escape such section when using bash.
---
The script is a bash function that sources all the files in a directory. it works fine form zsh (and it is irrelevant to the question)
```shell
#!/usr/bin/env bash
shell=$(ps -p $$ -oargs=)
if [ $shell = "bash" ]; then
for f in ~/.functions.d/*.sh; do source $f; done
elif [ $shell = "zsh" ]; then
for f (~/.functions.d/**/*.sh) source $f
fi
```
the error is produced by the 7th line, when sourcing it in `bash`
---
relevant links
- https://unix.stackexchange.com/questions/242854/source-only-part-of-a-script-from-another-script
- https://stackoverflow.com/questions/22183903/using-source-to-include-part-of-a-file-in-a-bash-script

#1: Initial revision by

4015.alt‭ · 2021-12-16T15:54:09Z (over 2 years ago)

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How to not source a part of a bash script?

I have a shell script with a syntax compatible to both `bash` and `zsh`, except for a section that has zsh specific syntax. that throws syntax errors if sourced from a bash 
is there **an easy way** to escape such section when using bash.

---

The script is a bash function that sources all the files in a directory. it works fine form zsh (and it is irreverent to the question)

```shell
#!/usr/bin/env bash

shell=$(ps -p $$ -oargs=)

if [ $shell = "bash" ]; then
	for f in ~/.functions.d/*.sh; do source $f; done
elif [ $shell = "zsh" ]; then
	for f (~/.functions.d/**/*.sh) source $f
fi
```

the error is produced by the 7th line, when sourcing it in `bash`

---

revilement links

- https://unix.stackexchange.com/questions/242854/source-only-part-of-a-script-from-another-script
- https://stackoverflow.com/questions/22183903/using-source-to-include-part-of-a-file-in-a-bash-script

shell bash shell-scripting zsh

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