Linux Systems

#8: Post edited by

AdminBee‭ · 2023-08-01T08:22:52Z (over 1 year ago)
Use same script name throughout

Copy Link

Raw

Markdown

If I understand you correctly, you want to
* skip empty lines at the beginning of a file/stream
* strip leading and trailing whitespace of non-empty lines
* skip empty lines at the end of a file/stream.[]()
This can be achieved using the following `awk` program:
```lang-bash
awk 'NF==0{if (m) {buf=buf RS}; next}
{if (!m) {m=1} else {printf "%s",buf;buf=""};sub(/^[[:blank:]]*/,"");sub(/[[:blank:]]*$/,"")}1'
```
This will do the following
1. If the line is (visually) empty, i.e. contains only space or nothing at all, it checks if a position flag `m` (for "main") is set. If set, a "newline" is added to a buffer variable `buf`. If not, the line is simply ignored and processing skipped to the `next` line.
2. If the line was not skipped, it is non-empty.
* In that case, if the flag `m` was not yet set the program has now reached the "main" part, so `m` is set to 1. Otherwise, it was already in the main part, and any buffered empty lines need to be printed now (but the buffer cleared). If there were no buffered empty lines, `buf` will be empty and nothing printed, hence no harm done.
* Then use `sub()` to strip the leading and trailing whitespace from the line.
* The seemingly stray `1` outside of the action blocks instructs `awk` to print the current line including all modifications made.
This ensures that leading and trailing empty lines are omitted while keeping (but if necessary sanitizing) internal empty lines.
If you want to omit trimming of the non-empty lines, you can simply skip the two calls to `sub()`.
---
This approach can be made more comfortable by placing the program in an `awk` script, say `strip_wsp.awk`:
```lang-awk
#!/usr/bin/awk -f
NF==0{
if (m) {buf=buf RS}
next
}
{
if (!m) {m=1} else {printf "%s",buf;buf=""}
if (trimlines) {
sub(/^[[:blank:]]*/,"")
sub(/[[:blank:]]*$/,"")
}
}
1
```
This version allows you to define an `awk` variable `trimlines` which, if set to non-zero, trims non-empty lines, but by default would leave them untouched:
Applied to a somewhat expanded version of your example string, the result is like this:
```lang-shellsession
~~$ printf -- "~~
~~hello~~
~~mellow~~
~~world~~
~~" | awk -v trimlines=1 -f trim_wsp.awk~~
hello
mellow
world
```

If I understand you correctly, you want to
* skip empty lines at the beginning of a file/stream
* strip leading and trailing whitespace of non-empty lines
* skip empty lines at the end of a file/stream.[]()
This can be achieved using the following `awk` program:
```lang-bash
awk 'NF==0{if (m) {buf=buf RS}; next}
{if (!m) {m=1} else {printf "%s",buf;buf=""};sub(/^[[:blank:]]*/,"");sub(/[[:blank:]]*$/,"")}1'
```
This will do the following
1. If the line is (visually) empty, i.e. contains only space or nothing at all, it checks if a position flag `m` (for "main") is set. If set, a "newline" is added to a buffer variable `buf`. If not, the line is simply ignored and processing skipped to the `next` line.
2. If the line was not skipped, it is non-empty.
* In that case, if the flag `m` was not yet set the program has now reached the "main" part, so `m` is set to 1. Otherwise, it was already in the main part, and any buffered empty lines need to be printed now (but the buffer cleared). If there were no buffered empty lines, `buf` will be empty and nothing printed, hence no harm done.
* Then use `sub()` to strip the leading and trailing whitespace from the line.
* The seemingly stray `1` outside of the action blocks instructs `awk` to print the current line including all modifications made.
This ensures that leading and trailing empty lines are omitted while keeping (but if necessary sanitizing) internal empty lines.
If you want to omit trimming of the non-empty lines, you can simply skip the two calls to `sub()`.
---
This approach can be made more comfortable by placing the program in an `awk` script, say `strip_wsp.awk`:
```lang-awk
#!/usr/bin/awk -f
NF==0{
if (m) {buf=buf RS}
next
}
{
if (!m) {m=1} else {printf "%s",buf;buf=""}
if (trimlines) {
sub(/^[[:blank:]]*/,"")
sub(/[[:blank:]]*$/,"")
}
}
1
```
This version allows you to define an `awk` variable `trimlines` which, if set to non-zero, trims non-empty lines, but by default would leave them untouched:
Applied to a somewhat expanded version of your example string, the result is like this:
```lang-shellsession
$ printf -- "
hello
mellow
world
" | awk -v trimlines=1 -f strip_wsp.awk
hello
mellow
world
```

#7: Post edited by

AdminBee‭ · 2023-07-31T14:51:21Z (over 1 year ago)
Updated command

Copy Link

Raw

Markdown

If I understand you correctly, you want to
* skip empty lines at the beginning of a file/stream
* strip leading and trailing whitespace of non-empty lines
* skip empty lines at the end of a file/stream.[]()
This can be achieved using the following `awk` program:
```lang-bash
awk 'NF==0{if (m) {buf=buf RS}; next}
~~{if (!m) {m=1} else {print buf;buf=""};sub(/^[[:blank:]]*/,"");sub(/[[:blank:]]*$/,"")}1'~~
```
This will do the following
1. If the line is (visually) empty, i.e. contains only space or nothing at all, it checks if a position flag `m` (for "main") is set. If set, a "newline" is added to a buffer variable `buf`. If not, the line is simply ignored and processing skipped to the `next` line.
2. If the line was not skipped, it is non-empty.
* In that case, if the flag `m` was not yet set the program has now reached the "main" part, so `m` is set to 1. Otherwise, it was already in the main part, and any buffered empty lines need to be printed now (but the buffer cleared). If there were no buffered empty lines, `buf` will be empty and nothing printed, hence no harm done.
* Then use `sub()` to strip the leading and trailing whitespace from the line.
* The seemingly stray `1` outside of the action blocks instructs `awk` to print the current line including all modifications made.
This ensures that leading and trailing empty lines are omitted while keeping (but if necessary sanitizing) internal empty lines.
If you want to omit trimming of the non-empty lines, you can simply skip the two calls to `sub()`.
---
This approach can be made more comfortable by placing the program in an `awk` script, say `strip_wsp.awk`:
```lang-awk
#!/usr/bin/awk -f
NF==0{
if (m) {buf=buf RS}
next
}
{
~~if (!m) {m=1} else {print buf;buf=""}~~
if (trimlines) {
sub(/^[[:blank:]]*/,"")
sub(/[[:blank:]]*$/,"")
}
}
1
```
This version allows you to define an `awk` variable `trimlines` which, if set to non-zero, trims non-empty lines, but by default would leave them untouched:
Applied to a somewhat expanded version of your example string, the result is like this:
```lang-shellsession
$ printf -- "\n \n hello\nmellow \n \n\nworld\n\n\n" | awk -v trimlines=1 -f trim_wsp.awk
hello
mellow
world
```

If I understand you correctly, you want to
* skip empty lines at the beginning of a file/stream
* strip leading and trailing whitespace of non-empty lines
* skip empty lines at the end of a file/stream.[]()
This can be achieved using the following `awk` program:
```lang-bash
awk 'NF==0{if (m) {buf=buf RS}; next}
{if (!m) {m=1} else {printf "%s",buf;buf=""};sub(/^[[:blank:]]*/,"");sub(/[[:blank:]]*$/,"")}1'
```
This will do the following
1. If the line is (visually) empty, i.e. contains only space or nothing at all, it checks if a position flag `m` (for "main") is set. If set, a "newline" is added to a buffer variable `buf`. If not, the line is simply ignored and processing skipped to the `next` line.
2. If the line was not skipped, it is non-empty.
* In that case, if the flag `m` was not yet set the program has now reached the "main" part, so `m` is set to 1. Otherwise, it was already in the main part, and any buffered empty lines need to be printed now (but the buffer cleared). If there were no buffered empty lines, `buf` will be empty and nothing printed, hence no harm done.
* Then use `sub()` to strip the leading and trailing whitespace from the line.
* The seemingly stray `1` outside of the action blocks instructs `awk` to print the current line including all modifications made.
This ensures that leading and trailing empty lines are omitted while keeping (but if necessary sanitizing) internal empty lines.
If you want to omit trimming of the non-empty lines, you can simply skip the two calls to `sub()`.
---
This approach can be made more comfortable by placing the program in an `awk` script, say `strip_wsp.awk`:
```lang-awk
#!/usr/bin/awk -f
NF==0{
if (m) {buf=buf RS}
next
}
{
if (!m) {m=1} else {printf "%s",buf;buf=""}
if (trimlines) {
sub(/^[[:blank:]]*/,"")
sub(/[[:blank:]]*$/,"")
}
}
1
```
This version allows you to define an `awk` variable `trimlines` which, if set to non-zero, trims non-empty lines, but by default would leave them untouched:
Applied to a somewhat expanded version of your example string, the result is like this:
```lang-shellsession
$ printf -- "\n \n hello\nmellow \n \n\nworld\n\n\n" | awk -v trimlines=1 -f trim_wsp.awk
hello
mellow
world
```

#6: Post edited by

AdminBee‭ · 2023-07-14T09:45:37Z (over 1 year ago)
Add script-file solution for convenience

Copy Link

Raw

Markdown

If I understand you correctly, you want to
* skip empty lines at the beginning of a file/stream
* strip leading and trailing whitespace of non-empty lines
* skip empty lines at the end of a file/stream.[]()
This can be achieved using the following `awk` program:
```lang-bash
awk 'NF==0{if (m) {buf=buf RS}; next}
{if (!m) {m=1} else {print buf;buf=""};sub(/^[[:blank:]]*/,"");sub(/[[:blank:]]*$/,"")}1'
```
This will do the following
1. If the line is (visually) empty, i.e. contains only space or nothing at all, it checks if a position flag `m` (for "main") is set. If set, a "newline" is added to a buffer variable `buf`. If not, the line is simply ignored and processing skipped to the `next` line.
2. If the line was not skipped, it is non-empty.
* In that case, if the flag `m` was not yet set the program has now reached the "main" part, so `m` is set to 1. Otherwise, it was already in the main part, and any buffered empty lines need to be printed now (but the buffer cleared). If there were no buffered empty lines, `buf` will be empty and nothing printed, hence no harm done.
* Then use `sub()` to strip the leading and trailing whitespace from the line.
* The seemingly stray `1` outside of the action blocks instructs `awk` to print the current line including all modifications made.
This ensures that leading and trailing empty lines are omitted while keeping (but if necessary sanitizing) internal empty lines.
If you want to omit trimming of the non-empty lines, you can simply skip the two calls to `sub()`.
Applied to a somewhat expanded version of your example string, the result is like this:
```lang-shellsession
~~$ printf -- "~~
~~hello~~
~~mellow~~
~~world~~
~~" |~~
awk 'NF==0{if (m) {buf=buf RS}; next}
~~{if (!m) {m=1} else {print buf;buf=""};sub(/^[[:blank:]]*/,"");sub(/[[:blank:]]*$/,"")}1'~~
hello
mellow
world
```

If I understand you correctly, you want to
* skip empty lines at the beginning of a file/stream
* strip leading and trailing whitespace of non-empty lines
* skip empty lines at the end of a file/stream.[]()
This can be achieved using the following `awk` program:
```lang-bash
awk 'NF==0{if (m) {buf=buf RS}; next}
{if (!m) {m=1} else {print buf;buf=""};sub(/^[[:blank:]]*/,"");sub(/[[:blank:]]*$/,"")}1'
```
This will do the following
1. If the line is (visually) empty, i.e. contains only space or nothing at all, it checks if a position flag `m` (for "main") is set. If set, a "newline" is added to a buffer variable `buf`. If not, the line is simply ignored and processing skipped to the `next` line.
2. If the line was not skipped, it is non-empty.
* In that case, if the flag `m` was not yet set the program has now reached the "main" part, so `m` is set to 1. Otherwise, it was already in the main part, and any buffered empty lines need to be printed now (but the buffer cleared). If there were no buffered empty lines, `buf` will be empty and nothing printed, hence no harm done.
* Then use `sub()` to strip the leading and trailing whitespace from the line.
* The seemingly stray `1` outside of the action blocks instructs `awk` to print the current line including all modifications made.
This ensures that leading and trailing empty lines are omitted while keeping (but if necessary sanitizing) internal empty lines.
If you want to omit trimming of the non-empty lines, you can simply skip the two calls to `sub()`.
---
This approach can be made more comfortable by placing the program in an `awk` script, say `strip_wsp.awk`:
```lang-awk
#!/usr/bin/awk -f
NF==0{
if (m) {buf=buf RS}
next
}
{
if (!m) {m=1} else {print buf;buf=""}
if (trimlines) {
sub(/^[[:blank:]]*/,"")
sub(/[[:blank:]]*$/,"")
}
}
1
```
This version allows you to define an `awk` variable `trimlines` which, if set to non-zero, trims non-empty lines, but by default would leave them untouched:
Applied to a somewhat expanded version of your example string, the result is like this:
```lang-shellsession
$ printf -- "
hello
mellow
world
" | awk -v trimlines=1 -f trim_wsp.awk
hello
mellow
world
```

#5: Post edited by

AdminBee‭ · 2023-07-13T08:05:45Z (over 1 year ago)
Include note on how to turn off whitespace-trimming on the non-empty lines. Use [:blank:] instead of [:space:] since only horizontal whitespace is to be trimmed there.

Copy Link

Raw

Markdown

If I understand you correctly, you want to
* skip empty lines at the beginning of a file/stream
* strip leading and trailing whitespace of non-empty lines
* skip empty lines at the end of a file/stream.[]()
This can be achieved using the following `awk` program:
```lang-bash
awk 'NF==0{if (m) {buf=buf RS}; next}
~~{if (!m) {m=1} else {print buf;buf=""};sub(/^[[:space:]]*/,"");sub(/[[:space:]]*$/,"")}1'~~
```
This will do the following
1. If the line is (visually) empty, i.e. contains only space or nothing at all, it checks if a position flag `m` (for "main") is set. If set, a "newline" is added to a buffer variable `buf`. If not, the line is simply ignored and processing skipped to the `next` line.
2. If the line was not skipped, it is non-empty.
* In that case, if the flag `m` was not yet set the program has now reached the "main" part, so `m` is set to 1. Otherwise, it was already in the main part, and any buffered empty lines need to be printed now (but the buffer cleared). If there were no buffered empty lines, `buf` will be empty and nothing printed, hence no harm done.
* Then use `sub()` to strip the leading and trailing whitespace from the line.
* The seemingly stray `1` outside of the action blocks instructs `awk` to print the current line including all modifications made.
This ensures that leading and trailing empty lines are omitted while keeping (but if necessary sanitizing) internal empty lines.
Applied to a somewhat expanded version of your example string, the result is like this:
```lang-shellsession
$ printf -- "\n \n hello\nmellow \n \n\nworld\n\n\n" |
awk 'NF==0{if (m) {buf=buf RS}; next}
~~{if (!m) {m=1} else {print buf;buf=""};sub(/^[[:space:]]*/,"");sub(/[[:space:]]*$/,"")}1'~~
hello
mellow
world
```

If I understand you correctly, you want to
* skip empty lines at the beginning of a file/stream
* strip leading and trailing whitespace of non-empty lines
* skip empty lines at the end of a file/stream.[]()
This can be achieved using the following `awk` program:
```lang-bash
awk 'NF==0{if (m) {buf=buf RS}; next}
{if (!m) {m=1} else {print buf;buf=""};sub(/^[[:blank:]]*/,"");sub(/[[:blank:]]*$/,"")}1'
```
This will do the following
1. If the line is (visually) empty, i.e. contains only space or nothing at all, it checks if a position flag `m` (for "main") is set. If set, a "newline" is added to a buffer variable `buf`. If not, the line is simply ignored and processing skipped to the `next` line.
2. If the line was not skipped, it is non-empty.
* In that case, if the flag `m` was not yet set the program has now reached the "main" part, so `m` is set to 1. Otherwise, it was already in the main part, and any buffered empty lines need to be printed now (but the buffer cleared). If there were no buffered empty lines, `buf` will be empty and nothing printed, hence no harm done.
* Then use `sub()` to strip the leading and trailing whitespace from the line.
* The seemingly stray `1` outside of the action blocks instructs `awk` to print the current line including all modifications made.
This ensures that leading and trailing empty lines are omitted while keeping (but if necessary sanitizing) internal empty lines.
If you want to omit trimming of the non-empty lines, you can simply skip the two calls to `sub()`.
Applied to a somewhat expanded version of your example string, the result is like this:
```lang-shellsession
$ printf -- "\n \n hello\nmellow \n \n\nworld\n\n\n" |
awk 'NF==0{if (m) {buf=buf RS}; next}
{if (!m) {m=1} else {print buf;buf=""};sub(/^[[:blank:]]*/,"");sub(/[[:blank:]]*$/,"")}1'
hello
mellow
world
```

#4: Post edited by

AdminBee‭ · 2023-07-12T13:13:06Z (over 1 year ago)
Break text for readability

Copy Link

Raw

Markdown

If I understand you correctly, you want to
* skip empty lines at the beginning of a file/stream
* strip leading and trailing whitespace of non-empty lines
* skip empty lines at the end of a file/stream.[]()
This can be achieved using the following `awk` program:
```lang-bash
awk 'NF==0{if (m) {buf=buf RS}; next}
{if (!m) {m=1} else {print buf;buf=""};sub(/^[[:space:]]*/,"");sub(/[[:space:]]*$/,"")}1'
```
This will do the following
1. If the line is (visually) empty, i.e. contains only space or nothing at all, it checks if a position flag `m` (for "main") is set. If set, a "newline" is added to a buffer variable `buf`. If not, the line is simply ignored and processing skipped to the `next` line.
2. If the line was not skipped, it is non-empty.
* In that case, if the flag `m` was not yet set the program has now reached the "main" part, so `m` is set to 1. Otherwise, it was already in the main part, and any buffered empty lines need to be printed now (but the buffer cleared). If there were no buffered empty lines, `buf` will be empty and nothing printed, hence no harm done.
* Then use `sub()` to strip the leading and trailing whitespace from the line.
* The seemingly stray `1` outside of the action blocks instructs `awk` to print the current line including all modifications made.
This ensures that leading and trailing empty lines are omitted while keeping (but if necessary sanitizing) internal empty lines.
Applied to a somewhat expanded version of your example string, the result is like this:
```lang-shellsession
~~$ printf -- "~~
~~hello~~
~~mellow~~
~~world~~
~~" | awk 'NF==0{if (m) {buf=buf RS}; next}~~
~~{if (!m) {m=1} else {print buf;buf=""};sub(/^[[:space:]]*/,"");sub(/[[:space:]]*$/,"")}1'~~
hello
mellow
world
```

If I understand you correctly, you want to
* skip empty lines at the beginning of a file/stream
* strip leading and trailing whitespace of non-empty lines
* skip empty lines at the end of a file/stream.[]()
This can be achieved using the following `awk` program:
```lang-bash
awk 'NF==0{if (m) {buf=buf RS}; next}
{if (!m) {m=1} else {print buf;buf=""};sub(/^[[:space:]]*/,"");sub(/[[:space:]]*$/,"")}1'
```
This will do the following
1. If the line is (visually) empty, i.e. contains only space or nothing at all, it checks if a position flag `m` (for "main") is set. If set, a "newline" is added to a buffer variable `buf`. If not, the line is simply ignored and processing skipped to the `next` line.
2. If the line was not skipped, it is non-empty.
* In that case, if the flag `m` was not yet set the program has now reached the "main" part, so `m` is set to 1. Otherwise, it was already in the main part, and any buffered empty lines need to be printed now (but the buffer cleared). If there were no buffered empty lines, `buf` will be empty and nothing printed, hence no harm done.
* Then use `sub()` to strip the leading and trailing whitespace from the line.
* The seemingly stray `1` outside of the action blocks instructs `awk` to print the current line including all modifications made.
This ensures that leading and trailing empty lines are omitted while keeping (but if necessary sanitizing) internal empty lines.
Applied to a somewhat expanded version of your example string, the result is like this:
```lang-shellsession
$ printf -- "
hello
mellow
world
" |
awk 'NF==0{if (m) {buf=buf RS}; next}
{if (!m) {m=1} else {print buf;buf=""};sub(/^[[:space:]]*/,"");sub(/[[:space:]]*$/,"")}1'
hello
mellow
world
```

#3: Post edited by

AdminBee‭ · 2023-07-12T13:05:13Z (over 1 year ago)
One prompt is enough

Copy Link

Raw

Markdown

If I understand you correctly, you want to
* skip empty lines at the beginning of a file/stream
* strip leading and trailing whitespace of non-empty lines
* skip empty lines at the end of a file/stream.[]()
This can be achieved using the following `awk` program:
```lang-bash
awk 'NF==0{if (m) {buf=buf RS}; next}
{if (!m) {m=1} else {print buf;buf=""};sub(/^[[:space:]]*/,"");sub(/[[:space:]]*$/,"")}1'
```
This will do the following
1. If the line is (visually) empty, i.e. contains only space or nothing at all, it checks if a position flag `m` (for "main") is set. If set, a "newline" is added to a buffer variable `buf`. If not, the line is simply ignored and processing skipped to the `next` line.
2. If the line was not skipped, it is non-empty.
* In that case, if the flag `m` was not yet set the program has now reached the "main" part, so `m` is set to 1. Otherwise, it was already in the main part, and any buffered empty lines need to be printed now (but the buffer cleared). If there were no buffered empty lines, `buf` will be empty and nothing printed, hence no harm done.
* Then use `sub()` to strip the leading and trailing whitespace from the line.
* The seemingly stray `1` outside of the action blocks instructs `awk` to print the current line including all modifications made.
This ensures that leading and trailing empty lines are omitted while keeping (but if necessary sanitizing) internal empty lines.
Applied to a somewhat expanded version of your example string, the result is like this:
```lang-shellsession
~~$ > printf -- "~~
~~hello~~
~~mellow~~
~~world~~
~~" | awk 'NF==0{if (m) {buf=buf RS}; next}~~
{if (!m) {m=1} else {print buf;buf=""};sub(/^[[:space:]]*/,"");sub(/[[:space:]]*$/,"")}1'
hello
mellow
world
```

If I understand you correctly, you want to
* skip empty lines at the beginning of a file/stream
* strip leading and trailing whitespace of non-empty lines
* skip empty lines at the end of a file/stream.[]()
This can be achieved using the following `awk` program:
```lang-bash
awk 'NF==0{if (m) {buf=buf RS}; next}
{if (!m) {m=1} else {print buf;buf=""};sub(/^[[:space:]]*/,"");sub(/[[:space:]]*$/,"")}1'
```
This will do the following
1. If the line is (visually) empty, i.e. contains only space or nothing at all, it checks if a position flag `m` (for "main") is set. If set, a "newline" is added to a buffer variable `buf`. If not, the line is simply ignored and processing skipped to the `next` line.
2. If the line was not skipped, it is non-empty.
* In that case, if the flag `m` was not yet set the program has now reached the "main" part, so `m` is set to 1. Otherwise, it was already in the main part, and any buffered empty lines need to be printed now (but the buffer cleared). If there were no buffered empty lines, `buf` will be empty and nothing printed, hence no harm done.
* Then use `sub()` to strip the leading and trailing whitespace from the line.
* The seemingly stray `1` outside of the action blocks instructs `awk` to print the current line including all modifications made.
This ensures that leading and trailing empty lines are omitted while keeping (but if necessary sanitizing) internal empty lines.
Applied to a somewhat expanded version of your example string, the result is like this:
```lang-shellsession
$ printf -- "
hello
mellow
world
" | awk 'NF==0{if (m) {buf=buf RS}; next}
{if (!m) {m=1} else {print buf;buf=""};sub(/^[[:space:]]*/,"");sub(/[[:space:]]*$/,"")}1'
hello
mellow
world
```

#2: Post edited by

AdminBee‭ · 2023-07-12T13:04:39Z (over 1 year ago)
Make explanation clearer

Copy Link

Raw

Markdown

~~If I understand you correctly, you want to strip~~
* empty lines at the beginning of a file/stream
* leading and trailing whitespace of non-empty lines
* empty lines at the end of a file/stream
This can be achieved using the following `awk` program:
```lang-bash
awk 'NF==0{if (m) {buf=buf RS}; next}
{if (!m) {m=1} else {print buf;buf=""};sub(/^[[:space:]]*/,"");sub(/[[:space:]]*$/,"")}1'
```
This will do the following
1. If the line is (visually) empty, i.e. contains only space or nothing at all, it checks if a position flag `m` (for "main") is set. If set, a "newline" is added to a buffer variable `buf`. If not, the line is simply ignored and processing skipped to the `next` line.
2. If the line was not skipped, it is non-empty.
* In that case, if the flag `m` was not yet set the program has now reached the "main" part, so `m` is set to 1. Otherwise, it was already in the main part, and any buffered empty lines need to be printed now (but the buffer cleared). If there were no buffered empty lines, `buf` will be empty and nothing printed, hence no harm done.
* Then use `sub()` to strip the leading and trailing whitespace from the line.
* The seemingly stray `1` outside of the action blocks instructs `awk` to print the current line including all modifications made.
This ensures that leading and trailing empty lines are omitted while keeping (but if necessary sanitizing) internal empty lines.
Applied to a somewhat expanded version of your example string, the result is like this:
```lang-shellsession
$ > printf -- "\n \n hello\nmellow \n \n\nworld\n\n\n" | awk 'NF==0{if (m) {buf=buf RS}; next}
{if (!m) {m=1} else {print buf;buf=""};sub(/^[[:space:]]*/,"");sub(/[[:space:]]*$/,"")}1'
hello
mellow
world
```

If I understand you correctly, you want to
* skip empty lines at the beginning of a file/stream
* strip leading and trailing whitespace of non-empty lines
* skip empty lines at the end of a file/stream.[]()
This can be achieved using the following `awk` program:
```lang-bash
awk 'NF==0{if (m) {buf=buf RS}; next}
{if (!m) {m=1} else {print buf;buf=""};sub(/^[[:space:]]*/,"");sub(/[[:space:]]*$/,"")}1'
```
This will do the following
1. If the line is (visually) empty, i.e. contains only space or nothing at all, it checks if a position flag `m` (for "main") is set. If set, a "newline" is added to a buffer variable `buf`. If not, the line is simply ignored and processing skipped to the `next` line.
2. If the line was not skipped, it is non-empty.
* In that case, if the flag `m` was not yet set the program has now reached the "main" part, so `m` is set to 1. Otherwise, it was already in the main part, and any buffered empty lines need to be printed now (but the buffer cleared). If there were no buffered empty lines, `buf` will be empty and nothing printed, hence no harm done.
* Then use `sub()` to strip the leading and trailing whitespace from the line.
* The seemingly stray `1` outside of the action blocks instructs `awk` to print the current line including all modifications made.
This ensures that leading and trailing empty lines are omitted while keeping (but if necessary sanitizing) internal empty lines.
Applied to a somewhat expanded version of your example string, the result is like this:
```lang-shellsession
$ > printf -- "\n \n hello\nmellow \n \n\nworld\n\n\n" | awk 'NF==0{if (m) {buf=buf RS}; next}
{if (!m) {m=1} else {print buf;buf=""};sub(/^[[:space:]]*/,"");sub(/[[:space:]]*$/,"")}1'
hello
mellow
world
```

#1: Initial revision by

AdminBee‭ · 2023-07-12T13:03:52Z (over 1 year ago)

Copy Link

Raw

Markdown

If I understand you correctly, you want to strip
* empty lines at the beginning of a file/stream
* leading and trailing whitespace of non-empty lines
* empty lines at the end of a file/stream

This can be achieved using the following `awk` program:
```lang-bash
awk 'NF==0{if (m) {buf=buf RS}; next}
          {if (!m) {m=1} else {print buf;buf=""};sub(/^[[:space:]]*/,"");sub(/[[:space:]]*$/,"")}1'
```
This will do the following
1. If the line is (visually) empty, i.e. contains only space or nothing at all, it checks if a position flag `m` (for "main") is set. If set, a "newline" is added to a buffer variable `buf`. If not, the line is simply ignored and processing skipped to the `next` line.
2. If the line was not skipped, it is non-empty.
   * In that case, if the flag `m` was not yet set the program has now reached the "main" part, so `m` is set to 1. Otherwise, it was already in the main part, and any buffered empty lines need to be printed now (but the buffer cleared). If there were no buffered empty lines, `buf` will be empty and nothing printed, hence no harm done.
   * Then use `sub()` to strip the leading and trailing whitespace from the line.
   * The seemingly stray `1` outside of the action blocks instructs `awk` to print the current line including all modifications made.

This ensures that leading and trailing empty lines are omitted while keeping (but if necessary sanitizing) internal empty lines.


Applied to a somewhat expanded version of your example string, the result is like this:
```lang-shellsession
$ > printf -- "\n \n hello\nmellow \n \n\nworld\n\n\n" | awk 'NF==0{if (m) {buf=buf RS}; next}
          {if (!m) {m=1} else {print buf;buf=""};sub(/^[[:space:]]*/,"");sub(/[[:space:]]*$/,"")}1'
hello

mellow



world
```

Communities

Post History