Adding Python 3.11 to `$PATH`
Hi, I'm new here. So basically I builded Python 3.11 (https://python.org/) from source (from GitHub python/cpython branch "3.11"). So, here what I did : (obviously first I downloaded the repo as ZIP)
cd Downloads 7z x cpython-3.11.zip cd cpython-3.11 chmod +x configure ./configure make
Everything is okay, I can run Python 3.11 only in the directory because it is not added to
And here is the problem.
What I tried :
- Rename the file
- Open the
.bashrcfile located in /home/[username]/
- Added that line of code at the end :
Note that my user name is
So I restarted my terminal and it does not work.
Can someone help please ?
I tried to do the same thing on the
.profile file but it still does not work. I tried to remove the quote marks but it still does not work.
There are two possible issues that I can see.
First, as already brought up in a comment thread, it appears that the
export command you added in your
.bashrc is missing a final
". This should cause an error message to be printed when starting a shell, making it an easy error to spot.
Second and more likely to be the problem,
$PATH points to directories to search for executable files; it does not point directly at specific executable files. So if you have a
python binary originally in the directory
~/cpython-3.11, then within that directory do a
mv python python3.11, then want to be able to start it by giving only its name (not a full path) you will need to add the directory it is in (
~/cpython-3.11) to your
Therefore, you should probably use something like
.bashrc in order to get the results you want.
Note that while changing
$PATH should be sufficient to make the shell invalidate cached command paths, you may need to start a whole new bash shell for it to actually pick up on the change. You can use
type -a python3.11 to get a list of all locations which your shell currently considers candidates for executing as a bare
python3.11, ordered by preference.
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