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Comments on When a command takes filenames as argument, how can I avoid creating temporary files?

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When a command takes filenames as argument, how can I avoid creating temporary files?

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Suppose I have a command that takes filenames as arguments, like: diff foo.txt bar.txt

What if instead of actual files, I want to use the results of a command in each?

I can use temporary files:

ls /home/alice > /tmp/alice.txt
ls /home/bob > /tmp/bob.txt
diff alice.txt bob.txt

But what if I don't want to create the files?

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What you're looking for is called process substitution.

In Bash and many bash-like shells, you can use <(foo_command --with --arguments) instead of the file path:

diff <(ls /home/alice) <(ls /home/bob)
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NB: I'm not marking "works for me" to encourage other folks to post better answers (if they want). Fo... (2 comments)
NB: I'm not marking "works for me" to encourage other folks to post better answers (if they want). Fo...
matthewsnyder‭ wrote over 1 year ago

NB: I'm not marking "works for me" to encourage other folks to post better answers (if they want). For example, I've only addressed Bash, which is honestly a pretty bad choice of shell in this day and age.

Also, it technically doesn't work for me, because I use fish. :) I have no idea what the syntax for fish is, nor do I care, because I avoid this syntax like the plague.

jimbobmcgee‭ wrote over 1 year ago

I have no idea what the syntax for fish

If memory serves, (command | psub) but, ironically, I think it just creates temp files under the hood...